-16x^2-96x+256=0

Solution for -16x^2-96x+256=0 equation:

-16x^2-96x+256=0

a = -16; b = -96; c = +256;
Δ = b2-4ac
Δ = -962-4·(-16)·256
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-160}{2*-16}=\frac{-64}{-32}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+160}{2*-16}=\frac{256}{-32}
=-8
$